orchidpsycho
New member
- Joined
- Sep 26, 2005
- Messages
- 41
was asked to make a table of values and sketch graph for the equation. find x and y intercepts and test for symmetry
y=x^2-3
got the graph with points (0,3) (1,-2) (2,1) (-1,-2) (-2,1) (-3,6) (3,6)
its symmetrical with respect to the y axis because the equation is unchanged when x is replaced with -x
the problem I am wondering is when i find the intercepts I get
y intercept= -3 (0,-3)
but the x I get +- sqrt[3] is that right. wasnt sure how I would present that?
thanks for any help.
y=x^2-3
got the graph with points (0,3) (1,-2) (2,1) (-1,-2) (-2,1) (-3,6) (3,6)
its symmetrical with respect to the y axis because the equation is unchanged when x is replaced with -x
the problem I am wondering is when i find the intercepts I get
y intercept= -3 (0,-3)
but the x I get +- sqrt[3] is that right. wasnt sure how I would present that?
thanks for any help.