#### mathdad

##### Full Member

- Joined
- Apr 24, 2015

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A total of 10,000 dollars is to be divided between Janet and Prissy, with Prissy to receive 3000 dollars less than Janet. How much will each receive?

Solution:

Divide 10,000 into two parts:

Prissy = x - 3000

Janet = x

x + x - 3000 = 10,000

2x - 3000 = 10,000

2x = 10,000 + 3000

2x =13,000

x = 13,000 ÷ 2

x = 6500

Janet will get 6500 dollars.

How about Prissy?

Prissy = x - 3000

Prissy = 6500 - 3000

Prissy = 3500

Prissy will get 3500 dollars.

PROVE:

Prissy + Janet = 10,000

3500 + 6500 = 10,000

10,000 = 10,000...It checks to be true.

What do you say?

Solution:

Divide 10,000 into two parts:

Prissy = x - 3000

Janet = x

x + x - 3000 = 10,000

2x - 3000 = 10,000

**..................................... typo edited**2x = 10,000 + 3000

2x =13,000

x = 13,000 ÷ 2

x = 6500

Janet will get 6500 dollars.

How about Prissy?

Prissy = x - 3000

Prissy = 6500 - 3000

Prissy = 3500

Prissy will get 3500 dollars.

PROVE:

Prissy + Janet = 10,000

3500 + 6500 = 10,000

10,000 = 10,000...It checks to be true.

What do you say?

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