Linear Equations: solve x/4 - 1/5 = (4x + 3) / 20 for x

crappiefisher26

New member
The instructions say to "Solve each of the following equations for x."

They don't give any examples though. I have tried one exercise, and this is what I got:

. . .x/4 - 1/5 = (4x + 3) / 20

. . .20[(x/4) - 20(1/5)] = 20[(4x + 3) / 20]

. . .5x - 4 = 4x + 3

. . .5x - 4x = 3 + 4

. . .x = 7

skeeter

Senior Member
check your solution by substituting 7 in for x in the original equation to see if it works.

Denis

Senior Member
Re: Linear Equation again

crappiefisher26 said:
x/4-1/5=4x+3 divided by 20
Post like this: x/4 - 1/5 = (4x + 3) / 20

stapel

Super Moderator
Staff member
crappiefisher26 said:
The instructions say to "Solve each of the following equations for x." They don't give any examples though....
Are you saying that your book does not actually cover the topic of solving linear equations, so you're asking for links to lessons, so you can learn...?

Thank you.

Eliz.

crappiefisher26

New member

um yeh. how bout this one.

(x/2)+3=6

6(x/2)+6(3/1)=6(6/1)

3x+2=1

subtract 2 on each side

ya get 3x=-1
divide each side by 3

x=-(1/3)

and this one who the heck knows.

(x/2)-(x/3)=2

would ya do the same thing or wut?

stapel

Super Moderator
Staff member
crappiefisher26 said:

crappiefisher26 said:
how bout this one.

Eliz.

jonboy

Full Member
crappiefisher26 said:
and this one who the heck knows.

(x/2)-(x/3)=2

would ya do the same thing or wut?
$$\displaystyle \L \frac{x}{2}\,-\,\frac{x}{3}\,=\,2$$

Multiply by 6 to since the LCM of 3 & 2 is 6. Whatever you do to the denominator ditto to the numerator.

$$\displaystyle \L \frac{3}{6}x\,-\, \frac{2}{6}x=\,2$$

$$\displaystyle \L \frac{1}{6}x=2$$

Solve for $$\displaystyle \L x$$