# Match the post#

#### ksdhart2

##### Senior Member
$$\displaystyle 0 + 12 + 3 \cdot 4 \cdot5 \cdot 6 + 789 = 1161$$

$$\displaystyle (9 \cdot 8+7-6+543 \cdot 2) + 1+0!=1161$$

#### lookagain

##### Senior Member
0! + 12 + 3*4*5*6 + 789 = 1162

√(9)*8 + 7*6*(5 + 4)*3 + 2 + 1 + 0! = 1162

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

ksdhart2, your second equation would be correct without the parentheses.

(Everyone here who uses the "(number expression)*number" format or "number*(number expression)" format
is being redundant (as I used in my second equation), too, because the parentheses don't require the asterisk.
I suspect it is to make the prior and/or following number stand out by being a little distance away from the
parentheses.

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#### Denis

##### Senior Member
01234 + 5 + 6 + 7 - 89 = 1163

987 + 6*5 - 4^3 + 210 = 1163

#### ksdhart2

##### Senior Member
$$\displaystyle 0! + 1234 + 5 + 6 + 7 - 89 = 1164$$

$$\displaystyle 9 \cdot 87 + 6 + 54 + 321 + 0 = 1164$$

#### Harry_the_cat

##### Senior Member
$$\displaystyle 0! + 1234 + 5 - 6 - 78 + 9 = 1165$$
$$\displaystyle 9*8 +(7 - 6) * 5+ 4^3 + 2^10 = 1165$$

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#### Harry_the_cat

##### Senior Member
$$\displaystyle 9*8 +(7-6)*5 +4^3 +2^{10} = 1165$$

$$\displaystyle 0+12^3 +4 -567-8+9 = 1166$$
$$\displaystyle 98+7*6-5+4+3+2^{10}=1166$$

#### Harry_the_cat

##### Senior Member
$$\displaystyle 0!+12^3 +4 -567-8+9 = 1167$$
$$\displaystyle 98+7*6+(5+4)\div3+2^{10}=1167$$

#### ksdhart2

##### Senior Member
$$\displaystyle 0 + 1 \cdot 23 \cdot 4 \cdot 5 + 6 + 78 \cdot 9 = 1168$$

$$\displaystyle 9 \cdot 8 \cdot 7 + 654 + 3^2 + 1 + 0 = 1168$$

#### Denis

##### Senior Member
$$\displaystyle 0! + 1 \cdot 23 \cdot 4 \cdot 5 + 6 + 78 \cdot 9 = 1169$$

$$\displaystyle 9 \cdot 8 \cdot 7 + 654 + 3^2 + 1 + 0! = 1169$$

#### Denis

##### Senior Member
-0! - 12 + 3 + 4^5 +67 + 89 = 1170

98 + (7 - 6)*5 + 43 + 2^10 = 1170

#### ksdhart2

##### Senior Member
$$\displaystyle 0 - 12 + 3 + 4^5 +67 + 89 = 1171$$

$$\displaystyle 987 + 6 \cdot 5 \cdot 4 + 3 \cdot 21 + 0! = 1171$$

#### Denis

##### Senior Member
(0! + 1) * (2 * 3 - 4 + 567 + 8 + 9) = 1172

(-9 + 8 + 7*6 + 543 + 2) * (1 + 0!) = 1172

#### lookagain

##### Senior Member
0 + 1 + 234*5 - 6 + 7 - 8 + 9 = 1173

-√(9) + (8 + 7)(6 + 5)(4 + 3) + 21 + 0 = 1173

#### lookagain

##### Senior Member
0! + 1 + 234*5 - 6 + 7 - 8 + 9 = 1174

-√(9) + (8 + 7)(6 + 5)(4 + 3) + 21 + 0! = 1174

#### Denis

##### Senior Member
(-0! - 12 + 3*4*5) * (6*7 - 8 - 9) = 1175

(-9 - 8 + 7*6) * (5 + 43 - 2 + 1 + 0) = 1175

#### Denis

##### Senior Member
0! + (1 - 2 + 3 + 45) * (6*7 - 8 - 9) = 1176

(-9-8 + 7*6) * (5 + 43 -2 + 1) + 0! = 1176

#### Harry_the_cat

##### Senior Member
$$\displaystyle 0*1^2-3+4^5+67+89=1177$$

$$\displaystyle 9+8+7+65+4^3+2^{10}=1177$$

#### ksdhart2

##### Senior Member
$$\displaystyle 0! \cdot 1^2-3+4^5+67+89=1178$$

$$\displaystyle 9 + 87 + 6 \cdot 5 \cdot 4 \cdot 3^2 + 1 + 0! = 1178$$

#### Denis

##### Senior Member
-0! - 1 - 2^3! + 456 + 789 = 1179

987 - 6 - 5 - 4 - 3 + 210 = 1179

#### Harry_the_cat

##### Senior Member
$$\displaystyle 0-1-2^{3!} +456 +789 =1180$$

$$\displaystyle (9+8+7+6-.5)*4*(3-2)*10=1180$$