A adabob New member Joined Jan 28, 2008 Messages 2 Jan 28, 2008 #1 Can someone help me figure out this problem? (6x to the negative second power y to the third power)raised to the negative 3rd Thanks for your help
Can someone help me figure out this problem? (6x to the negative second power y to the third power)raised to the negative 3rd Thanks for your help
O o_O Full Member Joined Oct 20, 2007 Messages 396 Jan 28, 2008 #2 Re: Negative Exponents \(\displaystyle \left(6x^{-2}y^{3}\right)^{-3}\) I'm guessing you need to simplify this. Two things that will help: \(\displaystyle \left(a^{m}\right)^{n} = a^{m \cdot n}\) \(\displaystyle a^{-n} = \frac{1}{a^{n}}\)
Re: Negative Exponents \(\displaystyle \left(6x^{-2}y^{3}\right)^{-3}\) I'm guessing you need to simplify this. Two things that will help: \(\displaystyle \left(a^{m}\right)^{n} = a^{m \cdot n}\) \(\displaystyle a^{-n} = \frac{1}{a^{n}}\)
A adabob New member Joined Jan 28, 2008 Messages 2 Jan 28, 2008 #3 Re: Negative Exponents That is the way I worked it and came up with x[sup:2vfjxr07]6[/sup:2vfjxr07]_____ 216y[sup:2vfjxr07]9[/sup:2vfjxr07] Does that look right?
Re: Negative Exponents That is the way I worked it and came up with x[sup:2vfjxr07]6[/sup:2vfjxr07]_____ 216y[sup:2vfjxr07]9[/sup:2vfjxr07] Does that look right?
O o_O Full Member Joined Oct 20, 2007 Messages 396 Jan 28, 2008 #4 Re: Negative Exponents Looks good to me!
