Relationship of circles and polygons

[Ihatdogs10]

Oh I messed up sorry
I forgot that their equivalent is their opposite

 

[Harry_the_cat]

It's important to get the CORRESPONDING SIDES together. The sides OX and OY are corresponding because they are both opposite the right angles, so they need to go together in a fraction.

 

[Ihatdogs10]

It's important to get the CORRESPONDING SIDES together. The sides OX and OY are corresponding because they are both opposite the right angles, so they need to go together in a fraction.

Ahh okay noted

 

[Harry_the_cat]

Once I've got the order correct ie POX matches up with QOY (matching their angles), then it's just a matter of pulling out letters 1&2, ie PO and QO, and then letters 2&3 ie OX and OY, and then letters 1&3. That's the easiest way.

 

[Ihatdogs10]

Once I've got the order correct ie POX matches up with QOY (matching their angles), then it's just a matter of pulling out letters 1&2, ie PO and QO, and then letters 2&3 ie OX and OY, and then letters 1&3. That's the easiest way.

to get their equivalent?

 

[Ihatdogs10]

thanks for the tip

 

[Harry_the_cat]

Nearly there.
So we have

Now go back to the original question, and note there is no OX and OY involved, so forget about the middle fraction.

to get their equivalent?

yeah

 

[Harry_the_cat]

thanks for the tip

You MUST have the order correct from the angles, before you do that.

 

[Ihatdogs10]

Nearly there.
So we have
View attachment 30101
Now go back to the original question, and note there is no OX and OY involved, so forget about the middle fraction.

yeah

okay so what am I going to do?

 

[Harry_the_cat]

Can you rearrange the statement \(\displaystyle \frac{PO}{QO}=\frac{PX}{QY}\) to get rid of fractions?

 

[Ihatdogs10]

PO AND QY = PX AND QO

 

[Harry_the_cat]

PO AND QY = PX AND QO

PO x QY = PX x QO Good!!

 

[Ihatdogs10]

Am I right?

 

[Ihatdogs10]

so what is the next step?

 

[Harry_the_cat]

You need mutiplication signs rather than "AND".

 

[Harry_the_cat]

What was the original question trying to get you to prove?

 

[Ihatdogs10]

that PX · QY = QY·PO

 

[Harry_the_cat]

that PX · QC = QY·PO

Remember the C is meant to be an O. (misprint in the question mentioned in a very early post)
Have a look at post #113.

 

[Ihatdogs10]

Remember the C is meant to be an O. (misprint in the question mentioned in a very early post)
Have a look at post #113.

Yes I edited it

 

[Harry_the_cat]

that PX · QY = QY·PO

should be PX . QO = QY . PO