"\(\displaystyle 1\times 10^{-14}\)" is a decimal point, 13 "0"s, then a "1": 0.00000000000001.

"\(\displaystyle 1.2\times 10^{-4}\)" is a decimal point, 3 "0"s, then "12": 0.00012.

\(\displaystyle \frac{0.00000000000001}{0.00012}\). Hopefully, you learned to divide such thing by first moving the decimal point in both numerator and denominator to the right 5 times so the denominator is a whole number: \(\displaystyle \frac{0.000000001}{12}\). And to do **that** division, you first write all of those "0"s in the numerator then think "I can't divide 10 by 12 so I write another 0 and append a 0 to the numerator: 100/12. 12*8= 96 so 12 goes into 100 8 times with remainder 100- 96= 4. Append another 0. 12 divides into 40 3 times, 3*12= 36, with remainder 4. and now we continue getting "3"s. \(\displaystyle \frac{0.00000000000001}{0.00012}= 0.0000000000000083333...\). The "..." indicates that the "3"s keep repeating without end.

Very tedious.

A little simpler is to write \(\displaystyle \frac{1\times 10^{-14}}{1.2\times 10^{-4}}= \frac{1}{1.2}\frac{10^{-14}}{10^{-4}}= \frac{1}{1.2}\times 10^{-14-(-4)}= \frac{1}{1.2}\times 10^{-10}\) and then calculate that \(\displaystyle \frac{1}{1.2}= 0.83333...= 8.333...\times 10^{-1}\) so that \(\displaystyle \frac{1\times 10^{-14}}{1.2\times 10^{-4}}= 8.333...\times 10^{-11}\).