Please help. (3x^-2 / 4x^3)^-3
P puzzled01 New member Joined Jun 15, 2007 Messages 12 Jun 28, 2007 #1 Please help. (3x^-2 / 4x^3)^-3
tkhunny Moderator Staff member Joined Apr 12, 2005 Messages 11,339 Jun 28, 2007 #2 (3x^-2 / 4x^3)^-3 I'll get you started. (4x^3 / 3x^-2)^3 Now what? Use your rules of exponents.
P puzzled01 New member Joined Jun 15, 2007 Messages 12 Jun 28, 2007 #3 I got 64x^15 / 27 is that right? Is that is far as I can go?
D Denis Senior Member Joined Feb 17, 2004 Messages 1,707 Jun 28, 2007 #4 puzzled01 said: Please help. (3x^-2 / 4x^3)^-3 Click to expand... 1: bring the x^3 to numerator position: (3x^-5 / 4)^-3 2: multiply inside powers by -3: 3^-3(x^15) / 4^-3 3: bring 3^-3 to denominator, 4^-3 to numerator: 4^3(x^15) / 3^3 If you can't follow that, see your teacher... EDIT: > I got 64x^15 / 27 is that right? YES! Good work :idea:
puzzled01 said: Please help. (3x^-2 / 4x^3)^-3 Click to expand... 1: bring the x^3 to numerator position: (3x^-5 / 4)^-3 2: multiply inside powers by -3: 3^-3(x^15) / 4^-3 3: bring 3^-3 to denominator, 4^-3 to numerator: 4^3(x^15) / 3^3 If you can't follow that, see your teacher... EDIT: > I got 64x^15 / 27 is that right? YES! Good work :idea:
tkhunny Moderator Staff member Joined Apr 12, 2005 Messages 11,339 Jun 28, 2007 #5 Good work! If you SHOW your correct work, I can pat you on the back even harder!