trying hard

G

Guest

Guest
[/quote][/code]

3/c-2 - 1/c+1 = 7/c^2 -c-2

This is how far I got: Could you tell me what I am doing wrong? And how to go far more:

3 1 7
===== - ====== = =======
c-2 c+1 (c-1) (c+2) LCD is (c-2)(c+2)


(c-2)(c+2)*(3 /c-2 - 1/ c+1) = (c-2)(c+2) (7/(c-1)(c-2))

(c+2) (3- 1/c+1) = 7

This is where I can't go any farther. Answer should be c=1

Sure do like you all! :wink: Hope I did it right this time with the code part!
 

pka

Elite Member
Joined
Jan 29, 2005
Messages
7,813
Code:
[code]
You MUST Type between the code symbols!
[/code]
 

Denis

Senior Member
Joined
Feb 17, 2004
Messages
1,459
3/c-2 - 1/c+1 = 7/c^2 -c-2
Nothing wrong with showing that way, BUT you need brackets:
3 / (c-2) - 1 / (c+1) = 7 / (c^2 - c - 2)

Here's a WHY example:
10 / 2 + 3 = 5 + 3 = 8
10 / (2 + 3) = 10 / 5 = 2 : clear nuff?

3 / (c-2) - 1 / (c+1) = 7 / (c^2 - c - 2)
[3 (c +1) - 1(c - 2)] / [(c-2) (c+1)] = 7 / [(c - 2)(c + 1)]

Since denominators are same, remove them:
[3 (c +1) - 1(c - 2)] = 7
3c + 3 - c + 2 = 7
3c - c = 7 - 3 - 2
2c = 2
c = 2/2 = 1

On the "remove denominators if same":
(2+3) / 7 = (1 + 4) / 7
2 + 3 = 1 + 4 : s'that clear?
 
G

Guest

Guest
Thanks

Not sure what you mean by typing between the code symbol???
I am so not user friendly....sorry.

Thanks Denis for your help. I am getting clearer on this. The only reason I am doing this math is so I can help my three children. My oldest son is in 9th and sometimes needs help with his math. Thanks.
 

tkhunny

Moderator
Staff member
Joined
Apr 12, 2005
Messages
9,784
Click on the code button. It will put the code in your text and it will change the button you clicked to include a star.

Without moving the cursor, type in what you wish.

Click on the Code* button

Yse preview to make minor adjustments.
 
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