Using Ohm's Law V=IR, find dI/dt when R=100 ohm, I=0.05 A

topsquark said:
You have two time rates of change given and you want the time rate of change of the third. Why not take the time derivative of each side?

[imath]\dfrac{dV}{dt} = \dfrac{d}{dt} (IR)[/imath]

Give it a try and if you still having problems, post what you get.

-Dan
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Dear Sir,

Grate thanks for the help
Can you please help me a bit little ahead

Thanks in advanced
 
1. Apply the Product Rule to find \(\displaystyle \frac{dV}{dt}\) given that \(\displaystyle V=IR\).

2. Then look at what you are given, eg you are given \(\displaystyle \frac{dR}{dt}=0.03\) ohms/s and what else?

3. And look at what you are asked to find, ie you are asked to find \(\displaystyle \frac {dI}{dt}\) for a given value of R and I.

As Topsquark said, give it a try, and ask for more help if you need it.
 
Harry_the_cat said:
1. Apply the Product Rule to find \(\displaystyle \frac{dV}{dt}\) given that \(\displaystyle V=IR\).

2. Then look at what you are given, eg you are given \(\displaystyle \frac{dR}{dt}=0.03\) ohms/s and what else?

3. And look at what you are asked to find, ie you are asked to find \(\displaystyle \frac {dI}{dt}\) for a given value of R and I.

As Topsquark said, give it a try, and ask for more help if you need it.
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It is still complicated for me
Can you please solve the full question that I will be easy to understand
This is grate help for me
 
Dan and Harry
Please tell me that the step that I have been done is correct
 

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I do not think you are ready for a course in differential equations because you seem to have trouble with basic differential calculus.

[math]y = uv \implies y’ = uv’ \text { PLUS } vu’[/math]
 
NotJeffM said:
I do not think you are ready for a course in differential equations because you seem to have trouble with basic differential calculus.

[math]y = uv \implies y’ = uv’ \text { PLUS } vu’[/math]
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Yes Thanks
Can you check that it is correct right now
 

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Hoped answer is correct please reply
 

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Re 3rd and 4th line: The left sides are exactly the same. Are the right side equal to one another? Why?
 
The 3rd line in the attachment (response# 13) is INCORRECT - and should be removed. The 4th line of that response is correct.
 
khansaheb said:
The 3rd line in the attachment (response# 13) is INCORRECT - and should be removed. The 4th line of that response is correct.
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I did not get it , Can you please solve it all the steps for me . It is great help
 
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