Using Ohm's Law V=IR, find dI/dt when R=100 ohm, I=0.05 A

[PA3040D]

The derivative of f(x)g(x) is NOT f'(x)*g'(x).
Based on the what you had for the 4th line, why would you write line 3?

This is the idea that i was written the line no 3 with respect to time (t)
If there is a wrong... can you please write the whole answer for me

 

[Steven G]

This is the idea that i was written the line no 3 with respect to time (t)
If there is a wrong... can you please write the whole answer for me

If you think the 3rd line is correct, then why did you write down and then use the 4th line

 

[Harry_the_cat]

This is the idea that i was written the line no 3 with respect to time (t)
If there is a wrong... can you please write the whole answer for me

Can you see that line 3 and line 4 are very different equations? They are NOT the same.

Line 3 is incorrect (as you have already been told) because the derivative of a product is NOT the product of the derivatives.

Line 4 uses the product rule to find the derivative of a product and is CORRECT.

Get rid of Line 3 and your working is correct.

Just fix up the value 0.5 as I mentioned before.