N nae New member Joined Jun 18, 2006 Messages 33 Jul 29, 2006 #1 Simplify the following: . . .3 / (wz^2) + 5 / [wz(3 + x)] The answer I got was 7/wz^2. Did I do this correctly? I added the numerator and got seven, and used the denominator by canceling the 3. If not, then I'm lost.

Simplify the following: . . .3 / (wz^2) + 5 / [wz(3 + x)] The answer I got was 7/wz^2. Did I do this correctly? I added the numerator and got seven, and used the denominator by canceling the 3. If not, then I'm lost.

tkhunny Moderator Staff member Joined Apr 12, 2005 Messages 9,778 Jul 29, 2006 #2 Just remember how to add fractions. \(\displaystyle \L\,\frac{3*(3+x)}{w*z^{2}*(3+x)}+\frac{5*z}{w*z^{2}*(3+x)} = \frac{3*(3+x)+5*z}{w*z^{2}*(3+x)}\)

Just remember how to add fractions. \(\displaystyle \L\,\frac{3*(3+x)}{w*z^{2}*(3+x)}+\frac{5*z}{w*z^{2}*(3+x)} = \frac{3*(3+x)+5*z}{w*z^{2}*(3+x)}\)

D Denis Senior Member Joined Feb 17, 2004 Messages 1,445 Jul 30, 2006 #3 nae, remember this: a/x + b/y = (ay + bx) / xy now try this: 2/3 + 5/6 = ?