what is the sum of the following

nae

New member
Joined
Jun 18, 2006
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33
Simplify the following:

. . .3 / (wz^2) + 5 / [wz(3 + x)]

The answer I got was 7/wz^2. Did I do this correctly? I added the numerator and got seven, and used the denominator by canceling the 3. If not, then I'm lost.
 
Just remember how to add fractions.

\(\displaystyle \L\,\frac{3*(3+x)}{w*z^{2}*(3+x)}+\frac{5*z}{w*z^{2}*(3+x)} = \frac{3*(3+x)+5*z}{w*z^{2}*(3+x)}\)
 
nae, remember this:

a/x + b/y = (ay + bx) / xy

now try this: 2/3 + 5/6 = ?
 
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