word problem

Diana

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Joined
Mar 28, 2006
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3
When the digits of a two-digit number are reversed, the new number is 9 more than the original number and the sum of the digits of the original number is 11. What is the original number?
 
let x = tens digit of the original number
y = units digit of the original number
so, original number has the value (10x + y)

When the digits of a two-digit number are reversed, the new number is 9 more than the original number ...

digits reversed (the new number) ... 10y + x

the new number is 9 more than the original number ...

10y + x = 9 + (10x + y)

sum of the digits of the original number is 11 ...
x + y = 11

you should be able to solve the problem using the last two equations.
 
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