Compound Inequalities

A single inequality doesn't always capture what you need. Temperature might need to be above freezing and below boiling. An age restriction might require being at least 16 but under 18. These situations call for compound inequalities — two inequality conditions combined into one statement.

Compound inequalities come in two flavors: AND inequalities (where both conditions must be true simultaneously) and OR inequalities (where satisfying either condition is enough).

AND Inequalities

An AND inequality requires both conditions to be satisfied at the same time. You're looking for the overlap: the values that make both inequalities true.

The classic way to write an AND inequality is: $a < x < b$

This is shorthand for: $x > a$ AND $x < b$

Example: $-2 < x < 4$

This means $x$ must be greater than -2 AND less than 4. So $x$ could be 0, 2, 3.9, or -1.5, but not -3 (too small) or 5 (too big).

On a number line, you'd put an open circle at -2 and another at 4, then shade the region between them. This shaded region represents all the numbers that satisfy both conditions.

Graph of -2 < x < 4 showing connected shaded region between -2 and 4

Example: Solve $-2 \leq y + 3 \leq 7$.

This is actually two inequalities in one:

$y + 3 \geq -2$
$y + 3 \leq 7$

Solve both at the same time by applying the same operation to all three parts.

Subtract 3 from all parts: $$-2 - 3 \leq y + 3 - 3 \leq 7 - 3$$ $$-5 \leq y \leq 4$$

The solution is all numbers between -5 and 4, including both endpoints. On a number line, put closed circles at -5 and 4, and shade between them.

Graph of -5 ≤ y ≤ 4 showing connected shaded region with closed circles

Example: Solve $1 < 2x - 3 < 9$.

Add 3 to all parts: $$1 + 3 < 2x - 3 + 3 < 9 + 3$$ $$4 < 2x < 12$$

Now divide all parts by 2 — what do you get? Show answer$2 < x < 6$. Graph: open circles at 2 and 6, shade between.

Writing Separate Inequalities as Compound Inequalities

Sometimes you'll see two separate inequalities that can be combined.

Example: Solve $x > -1$ AND $x \leq 4$.

These can be written as a single compound inequality: $-1 < x \leq 4$

Notice the inequality symbols point in different directions because one uses $<$ and the other uses $\leq$. The solution is all numbers greater than -1 up to and including 4.

Graph: open circle at -1, closed circle at 4, shade between.

Example: Solve $3x + 2 > 5$ AND $3x + 2 < 14$.

Solve the first inequality: $$3x + 2 > 5$$ $$3x > 3$$ $$x > 1$$

Solve the second inequality: $$3x + 2 < 14$$ $$3x < 12$$ $$x < 4$$

Combined: $1 < x < 4$

OR Inequalities

An OR inequality requires that at least one condition be true. The solution includes values that satisfy either inequality (or both, though with OR inequalities, that's often impossible).

Example: $x < -1$ OR $x > 3$

This means $x$ can be any number less than -1, or any number greater than 3. Numbers between -1 and 3 don't satisfy either condition, so they're not part of the solution.

On a number line, you'd put an open circle at -1 and shade everything to the left. Then put an open circle at 3 and shade everything to the right. You end up with two separate shaded regions.

Graph of x < -1 OR x > 3 showing two separate shaded regions

Example: Solve $2y - 3 < 1$ OR $2y - 3 > 7$.

Solve the first inequality: $$2y - 3 < 1$$ $$2y < 4$$ $$y < 2$$

Solve the second inequality: $$2y - 3 > 7$$ $$2y > 10$$ $$y > 5$$

Solution: $y < 2$ OR $y > 5$

Graph: open circle at 2, shade left. Open circle at 5, shade right.

Example: Solve $x + 4 \leq 1$ OR $x - 2 \geq 5$.

First inequality: $$x + 4 \leq 1$$ $$x \leq -3$$

Second inequality: $$x - 2 \geq 5$$ $$x \geq 7$$

Solution: $x \leq -3$ OR $x \geq 7$

Graph: closed circle at -3, shade left. Closed circle at 7, shade right.

How to Tell AND from OR

If you can write the compound inequality in the form $a < x < b$, it's an AND inequality. The solution is a single interval — a connected region on the number line.

If the solution has two separate regions with a gap in the middle, it's an OR inequality.

Comparison of AND vs OR inequalities showing connected vs separated regions

Another clue: AND inequalities use words like "between," "from...to," or "in the range of." OR inequalities use words like "either," "outside the range," or "less than...or greater than."

Special Cases

Example: Solve $x > 2$ AND $x > 5$.

If $x$ is greater than 5, it's automatically greater than 2. So the more restrictive condition is $x > 5$. That's the solution.

Graph: open circle at 5, shade right.

Example: Solve $x < 3$ OR $x < 7$.

Any number less than 3 is also less than 7, but there are numbers less than 7 that aren't less than 3 (like 5). The less restrictive condition is $x < 7$. That's the solution.

Graph: open circle at 7, shade left (which includes everything less than 3 anyway).

Example: Solve $x > 4$ AND $x < 1$.

This is impossible. No number can be both greater than 4 and less than 1 at the same time. The solution is the empty set (no solution).

Example: Solve $x > 4$ OR $x < 1$.

This doesn't cover numbers between 1 and 4, but it covers everything else.

Graph: open circle at 1, shade left. Open circle at 4, shade right.

Test Yourself

Solve and describe how you would graph each:

$3 < x + 1 < 8$ Show answerSubtract 1 from all parts: $2 < x < 7$. Graph: open circles at 2 and 7, shade between.
$x - 5 > 2$ OR $x + 3 < -1$ Show answerFirst: $x > 7$. Second: $x < -4$. Solution: $x < -4$ OR $x > 7$. Graph: open circle at -4 shade left, open circle at 7 shade right.
$-4 \leq 2y \leq 10$ Show answerDivide all parts by 2: $-2 \leq y \leq 5$. Graph: closed circles at -2 and 5, shade between.
$3m + 1 < -5$ OR $3m + 1 > 5$ Show answerFirst: $3m < -6$, so $m < -2$. Second: $3m > 4$, so $m > \frac{4}{3}$. Solution: $m < -2$ OR $m > \frac{4}{3}$. Graph: two separate regions.
$-1 < 3 - x < 5$ Show answerSubtract 3 from all parts: $-4 < -x < 2$. Multiply by -1 (flip both inequalities): $-2 < x < 4$. Graph: open circles at -2 and 4, shade between.

What's Next?

Two habits make compound inequalities much easier. With three-part inequalities like $a < b < c$, every operation applies to all three parts at once. Subtract 5? Subtract from all three. Divide by 2? Divide all three. If the divisor is negative, both inequality symbols flip — not just one. With OR inequalities, solve each piece on its own and combine the solutions only after both are done.

Always sketch the number line. The picture tells you immediately whether the solution is a connected region (AND) or two separated regions (OR), and it's an easy way to sanity-check your algebra. To verify, plug a value from your solution back into the original inequality and confirm it's true.

The next stop is systems of inequalities, which extends the same ideas into two variables and graphs in the coordinate plane.