volume of a barn

lev888 said:
It is 15ft. But I don't quite understand your question. Are you asking for permission? Or guessing? There is no guessing in math. You concluded that it's 15ft - fine, don't be afraid to say it.
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Yes, you're right. I'm still insecure.
15 because the length here is the distance between the two triangular bases.
 
Now, h2 being found, let's plug it in and solve for V
V= 1/2 (24*20.5)15

V=1/2(492)15

V=1/2(7380)

V=3690 ft^3

So the total volume of the barn is 2340+3690=6030 ft^3.
 
irspow said:
The volume of the rectangular prism below the roof is:

V=LWH You are given 24, 15, 6.5 ft
V=24*15*6.5= 2340 ft^3

Then you need to find the roof volume which will be the area of the triangle times the depth of the structure. You are told the peak is 9 yards or 27 feet from the ground. So the height of the triangles is 27-6.5=20.5 ft.

The area of the triangle is A=base*height/2. The total volume of the roof will be that area time the depth:
V=(bh/2)d, we know b=24, h=20.5, and d=15

V=(24/2)*(20.5)*15
V=3690 ft^3

So the total volume of the barn is 2340+3690=6030 ft^3
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Thanks a lot, I appreciated coming to my rescue. Lev is right ,though. When it comes to math, the best way is the hard way. Thanks again. Drop me hints and that will be a lot of help for me.
 
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